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Oracle 1Z0-829 certification exam is designed to help developers validate their skills and knowledge in developing applications using Java SE 17 technologies. Java SE 17 Developer certification is recognized worldwide and is a valuable asset for developers who want to enhance their career opportunities in the software development industry. Java SE 17 Developer certification exam is ideal for Java developers who want to demonstrate their expertise in Java programming and advance their careers in the field of software development.
NEW QUESTION # 30
Given:
Which statement is true?
- A. The program fails to compile.
- B. The program throws ClassCastException
- C. The program throws outofStockException.
- D. The program throws StockException.
Answer: A
Explanation:
Explanation
The answer is B because the code fragment contains a syntax error that prevents it from compiling. The code fragment tries to catch a StockException in line 10, but the catch block does not have a parameter of type StockException. The catch block should have a parameter of type StockException, such as:
catch (StockException e) { // handle the exception }
This is required by the Java syntax for the catch clause, which must have a parameter that is a subclass of Throwable. Without a parameter, the catch block is invalid and causes a compilation error.
Option A is incorrect because the program does not throw a StockException, as it does not compile.
Option C is incorrect because the program does not throw an OutofStockException, as it does not compile.
Option D is incorrect because the program does not throw a ClassCastException, as it does not compile.
References:
Oracle Certified Professional: Java SE 17 Developer
Java SE 17 Developer
OCP Oracle Certified Professional Java SE 17 Developer Study Guide
The try-with-resources Statement (The Java™ Tutorials > Essential Classes > Exceptions) The catch Blocks (The Java™ Tutorials > Essential Classes > Exceptions)
NEW QUESTION # 31
Given the code fragment:
abstract sealed interface SInt permits Story, Art { default String getTitle() { return "Book Title" ; }
}
Which set of class definitions compiles?
- A. Sealed interface Storty extends sInt {}
Non-sealed class Art implements Sint {} - B. Non-sealed interface story extends SInt {}
Non-sealed interaface Art extends Sint {} - C. Public interface story extends sInd {}
Public interface Art extends SInt {} - D. Interace story extends STnt {}
Interface Art extends SInt {} - E. Non-sealed interface story extends SInt {}
Class Art implements Sint {}
Answer: A
Explanation:
Explanation
The answer is C because the code fragment given is an abstract sealed interface SInt that permits Story and Art. The correct answer is option C, which is a sealed interface Story that extends SInt and a non-sealed class Art that implements SInt. This is because a sealed interface can only be extended by the classes or interfaces that it permits, and a non-sealed class can implement a sealed interface.
Option A is incorrect because interface is misspelled as interace, and Story and Art should be capitalized as they are the names of the permitted classes or interfaces.
Option B is incorrect because public is misspelled as public, and sInd should be SInt as it is the name of the sealed interface.
Option D is incorrect because a non-sealed interface cannot extend a sealed interface, as it would violate the restriction of permitted subtypes.
Option E is incorrect because both Story and Art cannot be non-sealed interfaces, as they would also violate the restriction of permitted subtypes.
References:
Oracle Certified Professional: Java SE 17 Developer
Java SE 17 Developer
OCP Oracle Certified Professional Java SE 17 Developer Study Guide
Sealed Classes and Interfaces in Java 15 | Baeldung
Sealed Class in Java - Javatpoint
NEW QUESTION # 32
Given:
What is the result?
- A. User name (EN - US)
- B. The program throws a MissingResourceException.
- C. User name (EN)
- D. User name (US)
- E. UserName
Answer: B
Explanation:
The answer is B because the code fragment contains a logical error that causes a MissingResourceException at runtime. The code fragment tries to load a resource bundle with the base name "Captions.properties" and the locale "en_US". However, there is no such resource bundle available in the classpath. The available resource bundles are:
Captions.properties
Captions_en.properties
Captions_US.properties
Captions_en_US.properties
The ResourceBundle class follows a fallback mechanism to find the best matching resource bundle for a given locale. It first tries to find the resource bundle with the exact locale, then it tries to find the resource bundle with the same language and script, then it tries to find the resource bundle with the same language, and finally it tries to find the default resource bundle with no locale. If none of these resource bundles are found, it throws a MissingResourceException.
In this case, the code fragment is looking for a resource bundle with the base name "Captions.properties" and the locale "en_US". The ResourceBundle class will try to find the following resource bundles in order:
Captions.properties_en_US
Captions.properties_en
Captions.properties
However, none of these resource bundles exist in the classpath. Therefore, the ResourceBundle class will throw a MissingResourceException.
To fix this error, the code fragment should use the correct base name of the resource bundle family, which is "Captions" without the ".properties" extension. For example:
ResourceBundle captions = ResourceBundle.getBundle("Captions", currentLocale); This will load the appropriate resource bundle for the current locale, which is "Captions_en_US.properties" in this case. Reference:
Oracle Certified Professional: Java SE 17 Developer
Java SE 17 Developer
OCP Oracle Certified Professional Java SE 17 Developer Study Guide
ResourceBundle (Java Platform SE 8 )
About the ResourceBundle Class (The Java™ Tutorials > Internationalization)
NEW QUESTION # 33
Given:
What is the result?
- A. Mb
- B. Mb
- C. MA
- D. mA
- E. Mb
MC
Answer: D
Explanation:
The code snippet is an example of Java SE 17 code. The code is checking if the object is an instance of class C and if it is, it will print "mC". If it is not an instance of class C, it will print "mA". In this case, the object is not an instance of class C, so the output will be "mA". Reference: Pattern Matching for instanceof - Oracle Help Center
NEW QUESTION # 34
Given the code fragment:
What is the result?
- A. 0
- B. 1
1
1 - C. 1
- D. 2
2
0 - E. 1
2
-4 - F. 2
Answer: A
Explanation:
Explanation
The code fragment uses the Collections.binarySearch method to search for the string "e3" in the list. The first search returns the index of the element, which is 2. The second search returns the index of the element, which is 0. The third search returns the index of the element, which is -4. The final result is
2. References: Collections (Java SE 17 & JDK 17) - Oracle
NEW QUESTION # 35
Given the code fragment:
What is the result:
- A. ABCDE // the order of elements is unpredictable
- B. ABBCDE // the order of elements is unpredictable
- C. ABCE
- D. ADEABCB // the order of element is unpredictable
Answer: B
Explanation:
The answer is D because the code fragment uses the Stream API to create two streams, s1 and s2, and then concatenates them using the concat() method. The resulting stream is then processed in parallel using the parallel() method, and the distinct() method is used to remove duplicate elements. Finally, the forEach() method is used to print the elements of the resulting stream to the console. Since the order of elements in a parallel stream is unpredictable, the output could be any of the options given, but option D is the most likely. Reference:
Oracle Certified Professional: Java SE 17 Developer
Java SE 17 Developer
OCP Oracle Certified Professional Java SE 17 Developer Study Guide
Parallelizing Streams
NEW QUESTION # 36
Given the code fragments:
Which action prints Wagon : 200?
- A. At Line n1, implement the java.io.AutoCloseable interface
- B. At line n2, in the main method signature, add throws IOException, ClassCastException.
- C. At line n2, in the main method signature, add throws IoException, ClassNotFoundException.
- D. At line n1, implement the java.io, Serializable interface.
- E. At line n3, replace readObject (0 with readLine().
- F. At Line n3, replace Car with LuxurayCar.
Answer: C
Explanation:
Explanation
The code fragment is trying to read an object from a file using the ObjectInputStream class. This class throws an IOException and a ClassNotFoundException. To handle these exceptions, the main method signature should declare that it throws these exceptions. Otherwise, the code will not compile. If the main method throws these exceptions, the code will print Wagon : 200, which is the result of calling the toString method of the LuxuryCar object that was written to the file. References: ObjectInputStream (Java SE 17 & JDK 17) - Oracle, ObjectOutputStream (Java SE 17 & JDK 17) - Oracle
NEW QUESTION # 37
Given:
What is the result?
- A. Software game write error
- B. Software Game Chess 2
- C. Software Game Software Game Chese 2
- D. Software Game Software Game chess 0
- E. Software Game Chess 0
- F. Software Game read error
Answer: C
Explanation:
Explanation
The answer is B because the code uses the writeObject and readObject methods of the ObjectOutputStream and ObjectInputStream classes to serialize and deserialize the Game object. These methods use the default serialization mechanism, which writes and reads the state of the object's fields, including the inherited ones. Therefore, the title field of the Software class is also serialized and deserialized along with the players field of the Game class. The toString method of the Game class calls the toString method of the Software class using super.toString(), which returns the value of the title field.
Hence, when the deserialized object is printed, it shows "Software Game Software Game Chess 2".
References:
Oracle Certified Professional: Java SE 17 Developer
Java SE 17 Developer
OCP Oracle Certified Professional Java SE 17 Developer Study Guide
Serialization and Deserialization in Java with Example
NEW QUESTION # 38
Given the code fragment:
Which code fragment invokes all callable objects in the workers set?
- A.
- B.
- C.
- D.
Answer: B
Explanation:
The code fragment in Option C invokes all callable objects in the workers set by using the ExecutorService's invokeAll() method. This method takes a collection of Callable objects and returns a list of Future objects representing the results of the tasks. The other options are incorrect because they either use the wrong method (invokeAny() or submit()) or have syntax errors (missing parentheses or semicolons). Reference: AbstractExecutorService (Java SE 17 & JDK 17) - Oracle
NEW QUESTION # 39
Given:
Which two modifications enable the code to print Open Close?
- A.
- B.
- C.
- D.
- E.
Answer: A,E
Explanation:
Explanation
The code given is a try-with-resources statement that declares a resource of type AutoCloseable. The resource is an anonymous class that implements the AutoCloseable interface and overrides the close() method. The code also has a print() method that prints the value of the variable s. The code is supposed to print "Open Close", but it does not compile because of two errors.
The first error is at line n1, where the anonymous class is missing a semicolon at the end of its declaration.
This causes a syntax error and prevents the code from compiling. To fix this error, option B adds a semicolon after the closing curly brace of the anonymous class.
The second error is at line n2, where the print() method is called without an object reference. This causes a compilation error because the print() method is not static and cannot be invoked without an object. To fix this error, option E adds an object reference to the print() method by using the variable t.
Therefore, options B and E are correct and enable the code to print "Open Close".
NEW QUESTION # 40
Given:
What is the result?
- A. A RuntimeException is thrown
- B. Tablechair Tablechair
- C. Wtablechair tableChair
- D. wTableChair TableChair
- E. Compilation fails
Answer: E
Explanation:
Explanation
The code fragment will fail to compile because the class name and the constructor name do not match. The class name is Furniture, but the constructor name is Wtable. This will cause a syntax error. The correct way to define a constructor is to use the same name as the class name. Therefore, the code fragment should change the constructor name to Furniture or change the class name to Wtable.
NEW QUESTION # 41
Given:
What is the result
- A. Marketing
- B. Marketing
Undefined - C. Marketing
Finance
Technical - D. UnDefined
Answer: D
Explanation:
Explanation
The code fragment is using the switch statement with the new Java 17 syntax. The switch statement checks the value of the variable desig and executes the corresponding case statement. In this case, the value of desig is
"CTO", which does not match any of the case labels. Therefore, the default case statement is executed, which prints "Undefined". The other case statements are not executed, because there is no fall through in the new syntax. Therefore, the output of the code fragment is:
Undefined
NEW QUESTION # 42
Given the code fragment:
Which two statements at Line nl independently enable you to print 1250?
- A. Integer res = 250 + s:
- B. Integer res = 250 + integer.parseint (s)
- C. Integer res = 250; Res = + s2;
- D. Integer res = 250 + integer (s2):
- E. Integer res= 250 + s2;
- F. Integer res = 250 + integer . valueof (s);
Answer: B,F
Explanation:
Explanation
The code fragment is creating a string variable "s" with the value "10_00" and an integer variable "s2" with the value 10. The string "s" is using an underscore as a separator for readability, which is allowed in Java SE
171. The question is asking for two statements that can add 250 to the numeric value of "s" and assign it to an integer variable "res". The correct answers are A and E because they use the methods parseInt and valueOf of the Integer class to convert the string "s" to an integer. Both methods interpret the string as a signed decimal integer and return the equivalent int or Integer value23. The other options are incorrect because they either use invalid syntax, such as B and C, or they do not convert the string "s" to an integer, such as D and F: References: Binary Literals (The Java™ Tutorials > Learning the Java Language > Numbers and Strings), Integer (Java SE 17 & JDK 17), Integer (Java SE 17 & JDK 17)
NEW QUESTION # 43
Given the content of the in. tart file:
23456789
and the code fragment:
What is the content of the out .txt file?
- A. 012345678
- B. 01234567801234
- C. 012345678901234
- D. 0123456789234567
- E. 0123456789
- F. 01234567
Answer: E
Explanation:
Explanation
The answer is D because the code fragment reads the content of the in.txt file and writes it to the out.txt file.
The content of the in.txt file is "23456789". The code fragment uses a char array buffer of size 8 to read the content of the in.txt file. The while loop reads the content of the in.txt file and writes it to the out.txt file until the end of the file is reached. Therefore, the content of the out.txt file will be "0123456789".
NEW QUESTION # 44
Given:
and the code fragment:
- A. 100.00 CellPhone,ToyCar
- B. 100.00
CellPhone,ToyCar,Motor,Fan - C. 300.00
CellPhone,ToyCar,Motor,Fan - D. 300.00
CellPhone.ToyCar
Answer: C
Explanation:
The code fragment is using the Stream API to perform a reduction operation on a list of ElectricProduct objects. The reduction operation consists of three parts: an identity value, an accumulator function, and a combiner function. The identity value is the initial value of the result, which is 0.0 in this case. The accumulator function is a BiFunction that takes two arguments: the current result and the current element of the stream, and returns a new result. In this case, the accumulator function is (a,b) -> a + b.getPrice (), which means that it adds the price of each element to the current result. The combiner function is a BinaryOperator that takes two partial results and combines them into one. In this case, the combiner function is (a,b) -> a + b, which means that it adds the two partial results together.
The code fragment then applies a filter operation on the stream, which returns a new stream that contains only the elements that match the given predicate. The predicate is p -> p.getPrice () > 10, which means that it selects only the elements that have a price greater than 10. The code fragment then applies a map operation on the filtered stream, which returns a new stream that contains the results of applying the given function to each element. The function is p -> p.getName (), which means that it returns the name of each element.
The code fragment then calls the collect method on the mapped stream, which performs a mutable reduction operation on the elements of the stream using a Collector. The Collector is Collectors.joining (","), which means that it concatenates the elements of the stream into a single String, separated by commas.
The code fragment then prints out the result of the reduction operation and the result of the collect operation, separated by a new line. The result of the reduction operation is 300.00, which is the sum of the prices of all ElectricProduct objects that have a price greater than 10. The result of the collect operation is CellPhone,ToyCar,Motor,Fan, which is the concatenation of the names of all ElectricProduct objects that have a price greater than 10.
Therefore, the output of the code fragment is:
300.00 CellPhone,ToyCar,Motor,Fan
NEW QUESTION # 45
Which statement is true?
- A. After the timed wait expires, the waited thread moves to the terminated state.
- B. A thread in waiting state must handle InterrupedException.
- C. IllegalStateException is thrown if a thread in waiting state is moved back to runnable.
- D. thread in waiting state consumes CPU cycles.
Answer: B
Explanation:
A thread in waiting state is waiting for another thread to perform a particular action, such as calling notify() or notifyAll() on a shared object, or terminating a joined thread. A thread in waiting state can be interrupted by another thread, which will cause the waiting thread to throw an InterruptedException and return to the runnable state. Therefore, a thread in waiting state must handle InterruptedException, either by catching it or declaring it in the throws clause. Reference: Thread.State (Java SE 17 & JDK 17), [Thread (Java SE 17 & JDK 17)]
NEW QUESTION # 46
Given the product class:
And the shop class:
What is the result?
- A. Cookie 0.0 2.99
- B. An exception is produced at runtime
- C. Cookie 0.0 0.0
- D. Cookie 2.99 2.99
- E. Compilation fails
- F. Cookie 3.99 2.99
Answer: E
Explanation:
The code fragment will fail to compile because the readObject method in the Product class is missing the @Override annotation. The readObject method is a special method that is used to customize the deserialization process of an object. It must be declared as private, have no return type, and take a single parameter of type ObjectInputStream. It must also be annotated with @Override to indicate that it overrides the default behavior of the ObjectInputStream class. Without the @Override annotation, the compiler will treat the readObject method as a normal method and not as a deserialization hook. Therefore, the code fragment will produce a compilation error. Reference: Object Serialization - Oracle, [ObjectInputStream (Java SE 17 & JDK 17) - Oracle]
NEW QUESTION # 47
Given the code fragment:
What is the result?
- A. true 1
false 2 - B. falase 0
true 1 - C. false 1
false 2 - D. false 1
ture 2
Answer: B
Explanation:
The code fragment is comparing the values of a, b, and c using the < and > operators. The first comparison, d, is checking if a is less than b and greater than c. Since a is equal to 2, b is equal to -2, and c is equal to -4, this comparison will evaluate to true. The second comparison, e, is checking if a is greater than b and a is greater than c. Since a is equal to 2, b is equal to -2, and c is equal to -4, this comparison will evaluate to false. Therefore, the result will be true 1 false 2. Reference: Operators (The Java™ Tutorials > Learning the Java Language - Oracle
NEW QUESTION # 48
Given the code fragment:
What is the result?
- A. 010 optional (Newyear)
- B. 0110
- C. True true false NewYear
- D. False true true optional (Newyear)
Answer: D
Explanation:
Explanation
The code fragment is using the stream methods allMatch, anyMatch, noneMatch, and findFirst on a list of strings called specialDays. These methods are used to perform matching operations on the elements of a stream, such as checking if all, any, or none of the elements satisfy a given predicate, or finding the first element that matches a predicate1. The predicate in this case is that the string equals "Labour" or
"Halloween". The output will be:
False: because not all of the elements in specialDays are equal to "Labour" or "Halloween".
true: because at least one of the elements in specialDays is equal to "Labour" or "Halloween".
true: because none of the elements in specialDays are equal to both "Labour" and "Halloween".
Optional[NewYear]: because the first element in specialDays that matches the predicate is "NewYear", and the findFirst method returns an Optional object that may or may not contain a non-null value2.
References: Stream (Java SE 17 & JDK 17), Optional (Java SE 17 & JDK 17)
NEW QUESTION # 49
Given:
What is the result?
- A. A RuntimeException is thrown
- B. Tablechair Tablechair
- C. Wtablechair tableChair
- D. wTableChair TableChair
- E. Compilation fails
Answer: E
Explanation:
The code fragment will fail to compile because the class name and the constructor name do not match. The class name is Furniture, but the constructor name is Wtable. This will cause a syntax error. The correct way to define a constructor is to use the same name as the class name. Therefore, the code fragment should change the constructor name to Furniture or change the class name to Wtable.
NEW QUESTION # 50
......
Oracle 1Z0-829 exam is an excellent opportunity for developers to demonstrate their expertise with Java SE 17 and advance their careers in the software development industry. With proper preparation and study, passing 1z1-829 exam can lead to career advancement and increased job opportunities.
Oracle 1Z0-829 certification exam covers a wide range of topics related to Java SE 17, including advanced concepts such as functional programming, modules, and concurrency. Candidates are expected to have a thorough understanding of the Java programming language, as well as experience in developing and deploying Java applications in production environments.
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