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IBM DB2 9 Family Fundamentals Sample Questions:

1. Which of the following statements is used to revoke all DML privileges on table EMPLOYEE from user TOM?

A) REVOKE EXECUTE ON EMPLOYEE FROM USER tom
B) REVOKE ALL ON EMPLOYEE FROM USER tom
C) REVOKE PRIVILEGES ON EMPLOYEE FROM USER tom
D) REVOKE ALL PRIVILEGES FROM USER tom

2. Which two of the following statements are true about the HAVING clause?

A) The HAVING clause accepts wildcards.
B) The HAVING clause uses the same syntax as the IN clause.
C) The HAVING clause is used in place of the WHERE clause.
D) The HAVING clause uses the same syntax as the WHERE clause.
E) The HAVING clause can only be used with the GROUP BY clause.

3. Which product must be installed on z/OS to allow a COBOL program running on that machine to access data on a remote DB2 for z/OS server?

A) DB2 Run-Time Client for z/OS
B) z/OS Application Connectivity to DB2 for z/OS and OS/390
C) DB2 for z/OS
D) DB2 Connect Enterprise Edition for z/OS

4. Given the following table:
CURRENT_EMPLOYEES
EMPID INTEGER NOT NULL
NAME CHAR(20)
SALARY DECIMAL(10,2)
PAST_EMPLOYEES
EMPID INTEGER NOT NULL
NAME CHAR(20)
SALARY DECIMAL(10,2)
Assuming both tables contain data, which of the following statements will NOT successfully add
data to table CURRENT_EMPLOYEES?

A) INSERT INTOcurrent_employees (empid) VALUES (10)
B) INSERT INTOcurrent_employees VALUES (10, 'JAGGER', 85000.00)
C) INSERT INTOcurrent_employees SELECT empid, name, salary FROM past_employees WHERE empid = 20
D) INSERT INTOcurrent_employees (name, salary) VALUES (SELECT name, salary FROM past_employees WHERE empid = 20)

5. Given the following two tables:
EMPLOYEE
ID NAME DEPTID
01 Mick Jagger 10 02 Keith Richards 20 03 Ronnie Wood 20 04 Charlie Watts 20 05 Bill Wyman 30 06 Brian Jones
DEPARTMENT
ID DEPTNAME
10 Executive Staff 20 Sales 30 Marketing 40 Engineering 50 Human Resources
Which two of the following queries will display the employee name and department name for all employees that are in Sales?

A) SELECT e.name,d.deptname FROM employee e RIGHT OUTER JOIN department d ON e.deptid = d.id
WHERE d.id = '20'
B) SELECT e.name,d.deptname FROM employee e, department d WHERE e.deptid = d.id AND d.id = '20'
C) SELECT e.name,d.deptname FROM employee e LEFT OUTER JOIN department d ON e.deptid = d.id WHERE d.id = '20'
D) SELECT e.name,d.deptname FROM employee e FULL OUTER JOIN department d ON e.deptid = d.id WHERE d.id = '20'
E) SELECT e.name,d.deptname FROM employee e INNER JOIN department d ON e.deptid = d.id WHERE d.id = '20'

Solutions: